What is the integral of 2/(3\sqrt[3]{x^2)} ?

The integral of 2/(3\sqrt[3]{x^2)} is 2\sqrt[3]{x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2/(3\sqrt[3]{x^2)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= \frac{2}{3} \cdot \int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= \frac{2}{3} \cdot 3 x^{\frac{1}{3}}

Simplify

Add a constant to the solution

y^{^{''}} + 16 y = sec (4 x)

\frac{d}{d x} (x^{3})

\int_{- 1}^{1} 2 - ∣ x ∣ - x^{4} d x

\frac{d y}{d x} = y^{4} sin (x)

\int \frac{2 ( 2 t - 1 )}{t ( 3 t ^{2} + 4 t - 1 )} d t

What is the integral of 2/(3\sqrt[3]{x^2)} ?
The integral of 2/(3\sqrt[3]{x^2)} is 2\sqrt[3]{x}+C