What is (\partial)/(\partial x)(x^2y+x+y) ?

The answer to (\partial)/(\partial x)(x^2y+x+y) is 2xy+1

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(\partial)/(\partial x)(x^2y+x+y)

\frac{\partial}{\partial x} (x^{2} y + x + y)

2 x y + 1

Solution steps

\frac{\partial}{\partial x} (x^{2} y + x + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} y) + \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= 2 y x + 1 + 0

Simplify

= 2 x y + 1

2 y^{^{''}} - 2 y^{^{'}} + 5 y = 0

\frac{d}{d x} (\frac{e ^{x}}{3 + e ^{x}})

\frac{d}{d x} (7 sin (x) - 2 x^{3})

\int \frac{x ^{2} + 36 x + 36}{x ^{3} - 4 x} d x

x \to 1 lim (\frac{x - 1}{ln ( x )})

What is (\partial)/(\partial x)(x^2y+x+y) ?
The answer to (\partial)/(\partial x)(x^2y+x+y) is 2xy+1