What is the solution for 121y^{''}-64y=0 ?

The solution for 121y^{''}-64y=0 is y=c_{1}e^{(8t)/(11)}+c_{2}e^{-(8t)/(11)}

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121y^{''}-64y=0

121 y^{^{''}} - 64 y = 0

y = c_{1} e^{\frac{8 t}{11}} + c_{2} e^{- \frac{8 t}{11}}

Solution steps

121 y^{''} (t) - 64 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{8 t}{11}} + c_{2} e^{- \frac{8 t}{11}}

y = c_{1} e^{\frac{8 t}{11}} + c_{2} e^{- \frac{8 t}{11}}

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What is the solution for 121y^{''}-64y=0 ?
The solution for 121y^{''}-64y=0 is y=c_{1}e^{(8t)/(11)}+c_{2}e^{-(8t)/(11)}