What is the derivative of g(x)=((9+6x)/(7-4x)) ?

The derivative of g(x)=((9+6x)/(7-4x)) is (78)/((7-4x)^2)

What is the first derivative of g(x)=((9+6x)/(7-4x)) ?

The first derivative of g(x)=((9+6x)/(7-4x)) is (78)/((7-4x)^2)

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derivative of

g (x) = (\frac{9 + 6 x}{7 - 4 x})

\frac{78}{( 7 - 4 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{9 + 6 x}{7 - 4 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 9 + 6 x ) ( 7 - 4 x ) - \frac{d}{d x} ( 7 - 4 x ) ( 9 + 6 x )}{( 7 - 4 x ) ^{2}}

\frac{d}{d x} (9 + 6 x) = 6

\frac{d}{d x} (7 - 4 x) = - 4

= \frac{6 ( 7 - 4 x ) - ( - 4 ) ( 9 + 6 x )}{( 7 - 4 x ) ^{2}}

Simplify

\frac{6 ( 7 - 4 x ) - ( - 4 ) ( 9 + 6 x )}{( 7 - 4 x ) ^{2}} : \frac{78}{( 7 - 4 x ) ^{2}}

= \frac{78}{( 7 - 4 x ) ^{2}}

\frac{\partial}{\partial z} (\frac{y}{z})

\frac{x}{1 + x}

\frac{d}{d x} ((A x^{2} + B x) e^{- x})

\frac{d}{d t} (\frac{2 t}{t ^{2} + 2})

arccot (3 x)

What is the derivative of g(x)=((9+6x)/(7-4x)) ?
The derivative of g(x)=((9+6x)/(7-4x)) is (78)/((7-4x)^2)
What is the first derivative of g(x)=((9+6x)/(7-4x)) ?
The first derivative of g(x)=((9+6x)/(7-4x)) is (78)/((7-4x)^2)