What is the derivative of tan(5x+1) ?

The derivative of tan(5x+1) is sec^2(5x+1)*5

What is the first derivative of tan(5x+1) ?

The first derivative of tan(5x+1) is sec^2(5x+1)*5

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\frac{d}{d x} (tan (5 x + 1))

sec^{2} (5 x + 1) \cdot 5

Solution steps

\frac{d}{d x} (tan (5 x + 1))

Apply the chain rule:

sec^{2} (5 x + 1) \frac{d}{d x} (5 x + 1)

= sec^{2} (5 x + 1) \frac{d}{d x} (5 x + 1)

\frac{d}{d x} (5 x + 1) = 5

= sec^{2} (5 x + 1) \cdot 5

x y^{2} y^{^{'}} = x + 6

n = 1 \sum \infty \frac{7}{n ^{6}}

y = \frac{x - 1}{x + 1}

x \to - 3 lim (g (x))

- \frac{40 x}{9 - 5 x ^{2}}

What is the derivative of tan(5x+1) ?
The derivative of tan(5x+1) is sec^2(5x+1)*5
What is the first derivative of tan(5x+1) ?
The first derivative of tan(5x+1) is sec^2(5x+1)*5