What is the derivative of h(t)=65-55cos((pit)/(15)) ?

The derivative of h(t)=65-55cos((pit)/(15)) is (11pi)/3 sin((pit)/(15))

What is the first derivative of h(t)=65-55cos((pit)/(15)) ?

The first derivative of h(t)=65-55cos((pit)/(15)) is (11pi)/3 sin((pit)/(15))

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derivative of

h (t) = 65 - 55 cos (\frac{π t}{15})

\frac{11 π}{3} sin (\frac{π t}{15})

Solution steps

\frac{d}{d t} (65 - 55 cos (\frac{π t}{15}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (65) - \frac{d}{d t} (55 cos (\frac{π t}{15}))

\frac{d}{d t} (65) = 0

\frac{d}{d t} (55 cos (\frac{π t}{15})) = - \frac{11 π}{3} sin (\frac{π t}{15})

= 0 - (- \frac{11 π}{3} sin (\frac{π t}{15}))

Simplify

= \frac{11 π}{3} sin (\frac{π t}{15})

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What is the derivative of h(t)=65-55cos((pit)/(15)) ?
The derivative of h(t)=65-55cos((pit)/(15)) is (11pi)/3 sin((pit)/(15))
What is the first derivative of h(t)=65-55cos((pit)/(15)) ?
The first derivative of h(t)=65-55cos((pit)/(15)) is (11pi)/3 sin((pit)/(15))