What is (\partial)/(\partial θ)(ρsin(φ)cos(θ)) ?

The answer to (\partial)/(\partial θ)(ρsin(φ)cos(θ)) is -ρsin(φ)sin(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial θ)(ρsin(φ)cos(θ))

\frac{\partial}{\partial θ} (ρ sin (φ) cos (θ))

- ρ sin (φ) sin (θ)

Solution steps

\frac{\partial}{\partial θ} (ρ sin (φ) cos (θ))

Treat

ρ, φ

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ρ sin (φ) \frac{\partial}{\partial θ} (cos (θ))

Apply the common derivative:

\frac{\partial}{\partial θ} (cos (θ)) = - sin (θ)

= ρ sin (φ) (- sin (θ))

Simplify

= - ρ sin (φ) sin (θ)

\frac{\partial}{\partial y} (ln (x^{2} y^{2}))

\frac{\partial}{\partial x} (arctan (5 x))

(9 y^{2} - x y) d x + x^{2} d y = 0

\int \frac{1}{x ^{2} + 10 x + 29} d x

f (x) = (arcsec (x))^{13}

What is (\partial)/(\partial θ)(ρsin(φ)cos(θ)) ?
The answer to (\partial)/(\partial θ)(ρsin(φ)cos(θ)) is -ρsin(φ)sin(θ)