What is the integral from 2 to infinity of 7/(3x^2) ?

The integral from 2 to infinity of 7/(3x^2) is 7/6

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integral from 2 to infinity of 7/(3x^2)

\int_{2}^{\infty} \frac{7}{3 x ^{2}} d x

\frac{7}{6}

Decimal Notation

1.16666 \dots

Solution steps

\int_{2}^{\infty} \frac{7}{3 x ^{2}} d x

Compute the indefinite integral:

\int \frac{7}{3 x ^{2}} d x = - \frac{7}{3 x} + C

Compute the boundaries:

\int_{2}^{\infty} \frac{7}{3 x ^{2}} d x = 0 - (- \frac{7}{6})

= 0 - (- \frac{7}{6})

Simplify

= \frac{7}{6}

\int \frac{1}{x ( x ^{2} - 36 ) ^{\frac{3}{2}}} d x

3 cos^{3} (t)

(ln (y))^{6} \frac{d y}{d x} = x^{6} y, y (1) = e^{2}

y = e^{x} (3 - 5 x + 3 x^{2})

n = 0 \sum \infty n^{2} + 1

What is the integral from 2 to infinity of 7/(3x^2) ?
The integral from 2 to infinity of 7/(3x^2) is 7/6