What is the integral of sqrt(x^9) ?

The integral of sqrt(x^9) is 2/11 x^{11/2}+C

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integral of sqrt(x^9)

\int x^{9} d x

\frac{2}{11} x^{\frac{11}{2}} + C

Solution steps

\int x^{9} d x

x^{9} = x^{\frac{9}{2}},

assuming

x \geq 0

= \int x^{\frac{9}{2}} d x

Apply the Power Rule

: \frac{2}{11} x^{\frac{11}{2}}

= \frac{2}{11} x^{\frac{11}{2}}

Add a constant to the solution

= \frac{2}{11} x^{\frac{11}{2}} + C

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What is the integral of sqrt(x^9) ?
The integral of sqrt(x^9) is 2/11 x^{11/2}+C