What is the solution for (dy)/(dx)=(x^3+2y^3)/(xy^2) ?

The solution for (dy)/(dx)=(x^3+2y^3)/(xy^2) is y=x\sqrt[3]{-1+c_{1}x^3}

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(dy)/(dx)=(x^3+2y^3)/(xy^2)

\frac{d y}{d x} = \frac{x ^{3} + 2 y ^{3}}{x y ^{2}}

y = x 3 - 1 + c_{1} x^{3}

Solution steps

\frac{d y}{d x} = \frac{x ^{3} + 2 y ^{3}}{x y ^{2}}

Solve Bernoulli ODE:

y = x 3 - 1 + c_{1} x^{3}

y = x 3 - 1 + c_{1} x^{3}

What is the solution for (dy)/(dx)=(x^3+2y^3)/(xy^2) ?
The solution for (dy)/(dx)=(x^3+2y^3)/(xy^2) is y=x\sqrt[3]{-1+c_{1}x^3}