What is the tangent of f(x)=2sec(x),\at x= pi/6 ?

The tangent of f(x)=2sec(x),\at x= pi/6 is y= 4/3 x+4/(sqrt(3))-(2pi)/9

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tangent of f(x)=2sec(x),\at x= pi/6

tangent of

f (x) = 2 sec (x), at x = \frac{π}{6}

y = \frac{4}{3} x + \frac{4}{3} - \frac{2 π}{9}

Solution steps

Find the tangent point:

(\frac{π}{6}, \frac{4}{3})

Find the slope of

f (x) = 2 sec (x) : \frac{df ( x )}{d x} = 2 sec (x) tan (x)

Compute the slope of

f (x) = 2 sec (x)

x = \frac{π}{6} : m = \frac{4}{3}

Find the line with slope m=

\frac{4}{3}

and passing through

(\frac{π}{6}, \frac{4}{3}) : y = \frac{4}{3} x + \frac{4}{3} - \frac{2 π}{9}

y = \frac{4}{3} x + \frac{4}{3} - \frac{2 π}{9}

(\frac{1}{y ^{2}} - \frac{5}{y ^{4}}) (y + 7 y^{3})

\frac{\partial}{\partial x} (\frac{x ^{α} y ^{β}}{y ^{1 - α} x ^{1 - β}})

\frac{d}{d x} ((e^{x})^{2})

sin (t^{2}) \cdot ln (t^{3})

\frac{\partial}{\partial x} ((1 + \frac{2}{y}) sin (x))

What is the tangent of f(x)=2sec(x),\at x= pi/6 ?
The tangent of f(x)=2sec(x),\at x= pi/6 is y= 4/3 x+4/(sqrt(3))-(2pi)/9