What is the d/(ds)(s/(s^2+9)) ?

The d/(ds)(s/(s^2+9)) is (-s^2+9)/((s^2+9)^2)

What is the first d/(ds)(s/(s^2+9)) ?

The first d/(ds)(s/(s^2+9)) is (-s^2+9)/((s^2+9)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d s} (\frac{s}{s ^{2} + 9})

\frac{- s ^{2} + 9}{( s ^{2} + 9 ) ^{2}}

Solution steps

\frac{d}{d s} (\frac{s}{s ^{2} + 9})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d s}{d s} ( s ^{2} + 9 ) - \frac{d}{d s} ( s ^{2} + 9 ) s}{( s ^{2} + 9 ) ^{2}}

\frac{d s}{d s} = 1

\frac{d}{d s} (s^{2} + 9) = 2 s

= \frac{1 \cdot ( s ^{2} + 9 ) - 2 ss}{( s ^{2} + 9 ) ^{2}}

1 \cdot (s^{2} + 9) - 2 ss = - s^{2} + 9

= \frac{- s ^{2} + 9}{( s ^{2} + 9 ) ^{2}}

\int \frac{1}{x ( x - 1 ) ^{3}} d x

\int 3 t e^{2 t} d t

x \to 1 lim (- 6 + 4 x^{2})

2 x - 5 y = 0, y = 0, x = 5

\frac{d}{d t} (e^{- t})

What is the d/(ds)(s/(s^2+9)) ?
The d/(ds)(s/(s^2+9)) is (-s^2+9)/((s^2+9)^2)
What is the first d/(ds)(s/(s^2+9)) ?
The first d/(ds)(s/(s^2+9)) is (-s^2+9)/((s^2+9)^2)