What is (\partial)/(\partial x)(e^{1x}cos(2y)) ?

The answer to (\partial)/(\partial x)(e^{1x}cos(2y)) is cos(2y)e^x

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(\partial)/(\partial x)(e^{1x}cos(2y))

\frac{\partial}{\partial x} (e^{1 x} cos (2 y))

cos (2 y) e^{x}

Solution steps

\frac{\partial}{\partial x} (e^{1 \cdot x} cos (2 y))

Simplify

e^{1 \cdot x} cos (2 y) : e^{x} cos (2 y)

= \frac{\partial}{\partial x} (e^{x} cos (2 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (2 y) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= cos (2 y) e^{x}

y^{^{''}} + y = 6 sin (2 t) + 4 t cos (2 t)

\frac{d}{d x} (600000 (0.8)^{x})

y = \frac{4}{ln ( x )}

\int \frac{x ^{4} + 1}{x ^{5} + 4 x ^{3}} d x

n = 1 \sum \infty (- 1)^{n - 1}

What is (\partial)/(\partial x)(e^{1x}cos(2y)) ?
The answer to (\partial)/(\partial x)(e^{1x}cos(2y)) is cos(2y)e^x