What is the solution for (4+x)y^'=3y ?

The solution for (4+x)y^'=3y is y=64e^{c_{1}}+48e^{c_{1}}x+12e^{c_{1}}x^2+e^{c_{1}}x^3

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(4+x)y^'=3y

(4 + x) y^{^{'}} = 3 y

y = 64 e^{c_{1}} + 48 e^{c_{1}} x + 12 e^{c_{1}} x^{2} + e^{c_{1}} x^{3}

Solution steps

(4 + x) y^{'} (x) = 3 y

Solve separable ODE:

y = 64 e^{c_{1}} + 48 e^{c_{1}} x + 12 e^{c_{1}} x^{2} + e^{c_{1}} x^{3}

y = 64 e^{c_{1}} + 48 e^{c_{1}} x + 12 e^{c_{1}} x^{2} + e^{c_{1}} x^{3}

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What is the solution for (4+x)y^'=3y ?
The solution for (4+x)y^'=3y is y=64e^{c_{1}}+48e^{c_{1}}x+12e^{c_{1}}x^2+e^{c_{1}}x^3