What is the integral of 1/(x*cos^2(ln(x))) ?

The integral of 1/(x*cos^2(ln(x))) is tan(ln(x))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(x*cos^2(ln(x)))

\int \frac{1}{x \cdot cos ^{2} ( ln ( x ) )} d x

tan (ln (x)) + C

Solution steps

\int \frac{1}{x cos ^{2} ( ln ( x ) )} d x

Apply u-substitution

: \int sec^{2} (u) d u

= \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= tan (u)

Substitute back

u = ln (x)

= tan (ln (x))

Add a constant to the solution

= tan (ln (x)) + C

x = 8 + 2 y, y = - 1, y = 3

x^{3} \frac{d y}{d x} + 5 x y = x

\frac{d h}{d t} = - 0.006 19.6 h

y = 1 + x, (4, 3)

\frac{d}{d x} (- \frac{1}{( 3 + x ) ^{2}})

What is the integral of 1/(x*cos^2(ln(x))) ?
The integral of 1/(x*cos^2(ln(x))) is tan(ln(x))+C