What is the limit as x approaches-3 of (x^3)/(x^2-9) ?

The limit as x approaches-3 of (x^3)/(x^2-9) is diverges

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limit as x approaches-3 of (x^3)/(x^2-9)

x \to - 3 lim (\frac{x ^{3}}{x ^{2} - 9})

diverges

Solution steps

x \to - 3 lim (\frac{x ^{3}}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 3 + lim (\frac{x ^{3}}{x ^{2} - 9}) = \infty

x \to - 3 - lim (\frac{x ^{3}}{x ^{2} - 9}) = - \infty

= diverges

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f (x) = e^{x}

\frac{d}{d x} (sin^{1} (x))

\frac{e ^{- 4 s}}{( 5 s ^{2} + 20 )}

\int (\frac{7}{t ^{2}} - 5 t^{5}) d t

What is the limit as x approaches-3 of (x^3)/(x^2-9) ?
The limit as x approaches-3 of (x^3)/(x^2-9) is diverges