What is the integral of (3/(x^4)) ?

The integral of (3/(x^4)) is -1/(x^3)+C

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integral of (3/(x^4))

\int (\frac{3}{x ^{4}}) d x

- \frac{1}{x ^{3}} + C

Solution steps

\int \frac{3}{x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x ^{4}} d x

Apply the Power Rule

: - \frac{1}{3 x ^{3}}

= 3 (- \frac{1}{3 x ^{3}})

Simplify

3 (- \frac{1}{3 x ^{3}}) : - \frac{1}{x ^{3}}

= - \frac{1}{x ^{3}}

Add a constant to the solution

= - \frac{1}{x ^{3}} + C

\frac{\partial}{\partial y} (e^{y x})

\frac{\partial}{\partial x} (4 x + 9 y - 360)

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x + 1})

f (x) = x^{3} + 9 x^{2} + x + 9

\int \frac{( x - 2 ) ^{3}}{x ^{2}} d x