What is the integral of (x/3)^3 ?

The integral of (x/3)^3 is (x^4)/(27)-(x^4)/(36)+C

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integral of (x/3)^3

\int (\frac{x}{3})^{3} d x

\frac{x ^{4}}{27} - \frac{x ^{4}}{36} + C

Solution steps

\int (\frac{x}{3})^{3} d x

Apply Integration By Parts

: \frac{x ^{4}}{27} - \int \frac{x ^{3}}{9} d x

= \frac{x ^{4}}{27} - \int \frac{x ^{3}}{9} d x

\int \frac{x ^{3}}{9} d x = \frac{x ^{4}}{36}

= \frac{x ^{4}}{27} - \frac{x ^{4}}{36}

Add a constant to the solution

= \frac{x ^{4}}{27} - \frac{x ^{4}}{36} + C

x \to 1 lim (\frac{7}{x ^{3} - 1})

4 t^{- \frac{3}{8}} + 5 ln (t) + ln (5)

\int e^{x} (1 + e^{x})^{\frac{1}{2}} d x

x \to 0 lim (\frac{1}{x} - \frac{1}{x ^{2} - x})

What is the integral of (x/3)^3 ?
The integral of (x/3)^3 is (x^4)/(27)-(x^4)/(36)+C