What is the derivative of 2x+x^2 ?

The derivative of 2x+x^2 is 2+2x

What is the first derivative of 2x+x^2 ?

The first derivative of 2x+x^2 is 2+2x

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\frac{d}{d x} (2 x + x^{2})

2 + 2 x

Solution steps

\frac{d}{d x} (2 x + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (x^{2}) = 2 x

= 2 + 2 x

\int tan^{2} (8 x) d x

y = \frac{e ^{x}}{x - 1}

\frac{d y}{d x} = \frac{( e ^{- y} + e ^{- 5 x - y} )}{e ^{x} y}

x \to 1 lim (- 9 + 3 x^{2})

\int t^{2} - t^{4} \frac{d}{1} d t