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Popular >

e^{2x}y^'-4y=0

Solution

e^{2 x} y^{^{'}} - 4 y = 0

Solution

y = e^{- 2 e^{- 2 x} + c_{1}}

Solution steps

e^{2 x} y^{'} (x) - 4 y = 0

Solve separable ODE:

y = e^{- 2 e^{- 2 x} + c_{1}}

y = e^{- 2 e^{- 2 x} + c_{1}}

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\int 2 (cos (x))^{- \frac{1}{2}} sin (x) d x

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\int \frac{5 x ^{2}}{( x + 1 ) ( x ^{2} + 1 )} d x

Frequently Asked Questions (FAQ)

What is the solution for e^{2x}y^'-4y=0 ?
The solution for e^{2x}y^'-4y=0 is y=e^{-2e^{-2x}+c_{1}}