What is (\partial)/(\partial x)(6y^2+478x-10) ?

The answer to (\partial)/(\partial x)(6y^2+478x-10) is 478

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(\partial)/(\partial x)(6y^2+478x-10)

\frac{\partial}{\partial x} (6 y^{2} + 478 x - 10)

478

Solution steps

\frac{\partial}{\partial x} (6 y^{2} + 478 x - 10)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (6 y^{2}) + \frac{\partial}{\partial x} (478 x) - \frac{\partial}{\partial x} (10)

\frac{\partial}{\partial x} (6 y^{2}) = 0

\frac{\partial}{\partial x} (478 x) = 478

\frac{\partial}{\partial x} (10) = 0

= 0 + 478 - 0

Simplify

= 478

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\frac{d}{d x} (2 (x - 2))

\frac{d}{d x} ((\frac{cos ( x )}{1 - sin ( x )})^{2})

\int \frac{1}{( 1 + 2 x )} d x

What is (\partial)/(\partial x)(6y^2+478x-10) ?
The answer to (\partial)/(\partial x)(6y^2+478x-10) is 478