What is the limit as x approaches 0 of 4cos(2x) ?

The limit as x approaches 0 of 4cos(2x) is 4

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limit as x approaches 0 of 4cos(2x)

x \to 0 lim (4 cos (2 x))

4

Solution steps

x \to 0 lim (4 cos (2 x))

Plug in the value

x = 0

= 4 cos (2 \cdot 0)

Simplify

4 cos (2 \cdot 0) : 4

= 4

y^{^{''}} - y^{^{'}} = 6 x e^{x}

x \to 0 lim (x^{3} - 3 x^{2} + 2 x - 3)

2 y^{^{''}} - 32 y = 0

\frac{d}{d x} (- 12 x^{2})

What is the limit as x approaches 0 of 4cos(2x) ?
The limit as x approaches 0 of 4cos(2x) is 4