What is the derivative of (x^2-3x)/2 ?

The derivative of (x^2-3x)/2 is x-3/2

What is the first derivative of (x^2-3x)/2 ?

The first derivative of (x^2-3x)/2 is x-3/2

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derivative of

\frac{x ^{2} - 3 x}{2}

x - \frac{3}{2}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 3 x}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= \frac{1}{2} (2 x - 3)

Simplify

\frac{1}{2} (2 x - 3) : x - \frac{3}{2}

= x - \frac{3}{2}

ln (x + x^{2} + 1)

x \to \infty lim (\frac{x}{( ln ( x ) ) ^{3} + 2 x})

2 y \frac{d y}{d x} = \frac{x}{x ^{2} - 16}, y (5) = 2

\int 9 x - 36 d x

\frac{d y}{d x} = 10 e^{x - y}

What is the derivative of (x^2-3x)/2 ?
The derivative of (x^2-3x)/2 is x-3/2
What is the first derivative of (x^2-3x)/2 ?
The first derivative of (x^2-3x)/2 is x-3/2