What is the derivative of f(x)=(-16x^2+1)^2 ?

The derivative of f(x)=(-16x^2+1)^2 is -64x(-16x^2+1)

What is the first derivative of f(x)=(-16x^2+1)^2 ?

The first derivative of f(x)=(-16x^2+1)^2 is -64x(-16x^2+1)

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derivative of

f (x) = (- 16 x^{2} + 1)^{2}

- 64 x (- 16 x^{2} + 1)

Solution steps

\frac{d}{d x} ((- 16 x^{2} + 1)^{2})

Apply the chain rule:

2 (- 16 x^{2} + 1) \frac{d}{d x} (- 16 x^{2} + 1)

= 2 (- 16 x^{2} + 1) \frac{d}{d x} (- 16 x^{2} + 1)

\frac{d}{d x} (- 16 x^{2} + 1) = - 32 x

= 2 (- 16 x^{2} + 1) (- 32 x)

Simplify

= - 64 x (- 16 x^{2} + 1)

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What is the derivative of f(x)=(-16x^2+1)^2 ?
The derivative of f(x)=(-16x^2+1)^2 is -64x(-16x^2+1)
What is the first derivative of f(x)=(-16x^2+1)^2 ?
The first derivative of f(x)=(-16x^2+1)^2 is -64x(-16x^2+1)