What is (\partial)/(\partial y)(e^{ax+y}+e^y) ?

The answer to (\partial)/(\partial y)(e^{ax+y}+e^y) is e^{ax+y}+e^y

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(\partial)/(\partial y)(e^{ax+y}+e^y)

\frac{\partial}{\partial y} (e^{a x + y} + e^{y})

e^{a x + y} + e^{y}

Solution steps

\frac{\partial}{\partial y} (e^{a x + y} + e^{y})

Treat

a, x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{a x + y}) + \frac{\partial}{\partial y} (e^{y})

\frac{\partial}{\partial y} (e^{a x + y}) = e^{a x + y}

\frac{\partial}{\partial y} (e^{y}) = e^{y}

= e^{a x + y} + e^{y}

a^{(\frac{1}{2})} (7 x - a) + 2 a

x - x^{3}

x^{\frac{1}{3} + y^{\frac{1}{3}}} = 7

y^{^{''}} - 2 y^{^{'}} + 17 y = 0

x \to 1 lim (\frac{- 1}{x})

What is (\partial)/(\partial y)(e^{ax+y}+e^y) ?
The answer to (\partial)/(\partial y)(e^{ax+y}+e^y) is e^{ax+y}+e^y