What is (\partial)/(\partial u)(vsin(u)) ?

The answer to (\partial)/(\partial u)(vsin(u)) is vcos(u)

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(\partial)/(\partial u)(vsin(u))

\frac{\partial}{\partial u} (v sin (u))

v cos (u)

Solution steps

\frac{\partial}{\partial u} (v sin (u))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= v \frac{\partial}{\partial u} (sin (u))

Apply the common derivative:

\frac{\partial}{\partial u} (sin (u)) = cos (u)

= v cos (u)

\frac{d}{d x} (2 sec (x))

\frac{d}{d x} (\frac{3 - 8 x}{x + 4})

\frac{s ^{3} + s + 6}{s ^{4} ( s + 2 )}

\int_{7}^{8} \frac{x}{x ^{2} - 3} d x

What is (\partial)/(\partial u)(vsin(u)) ?
The answer to (\partial)/(\partial u)(vsin(u)) is vcos(u)