What is the solution for 2xy^'+y=10sqrt(x) ?

The solution for 2xy^'+y=10sqrt(x) is y=5sqrt(x)+(c_{1})/(sqrt(x))

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2xy^'+y=10sqrt(x)

2 x y^{^{'}} + y = 10 x

y = 5 x + \frac{c _{1}}{x}

Solution steps

2 x y^{'} (x) + y = 10 x

Solve linear ODE:

y = 5 x + \frac{c _{1}}{x}

y = 5 x + \frac{c _{1}}{x}

\frac{d}{d x} (\frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}})

\int (x^{3} + 1)^{3} d x

f (x) = \frac{8}{7 x ^{2}}

f (x) = x^{2} - 2 x + 1

What is the solution for 2xy^'+y=10sqrt(x) ?
The solution for 2xy^'+y=10sqrt(x) is y=5sqrt(x)+(c_{1})/(sqrt(x))