What is the derivative of f(x)=e^{x+1} ?

The derivative of f(x)=e^{x+1} is e^{x+1}

What is the first derivative of f(x)=e^{x+1} ?

The first derivative of f(x)=e^{x+1} is e^{x+1}

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derivative of

f (x) = e^{x + 1}

e^{x + 1}

Solution steps

\frac{d}{d x} (e^{x + 1})

Apply the chain rule:

e^{x + 1} \frac{d}{d x} (x + 1)

= e^{x + 1} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= e^{x + 1} \cdot 1

Simplify

= e^{x + 1}

x^{\frac{1}{3}} + \frac{x - 4}{3 x ^{\frac{5}{3}}}

\frac{d}{d x} (- sin (x^{2} + 3) \cdot 2 x)

\int 5 x^{2} (2 x^{3} + 3)^{4} d x

\int \frac{( ln ( ln ( x ) ) )}{x} d x

What is the derivative of f(x)=e^{x+1} ?
The derivative of f(x)=e^{x+1} is e^{x+1}
What is the first derivative of f(x)=e^{x+1} ?
The first derivative of f(x)=e^{x+1} is e^{x+1}