What is the integral of (cot^2(x))/(cos^2(x)) ?

The integral of (cot^2(x))/(cos^2(x)) is -cot(x)+C

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integral of (cot^2(x))/(cos^2(x))

\int \frac{cot ^{2} ( x )}{cos ^{2} ( x )} d x

- cot (x) + C

Solution steps

\int \frac{cot ^{2} ( x )}{cos ^{2} ( x )} d x

Simplify

\frac{cot ^{2} ( x )}{cos ^{2} ( x )} : csc^{2} (x)

= \int csc^{2} (x) d x

Use the common integral:

\int csc^{2} (x) d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

\frac{d}{d x} (\frac{1}{4} (e^{2 x} + e^{- 2 x}))

\frac{d}{d x} (\frac{x ^{3} - x ^{2} + 1}{5})

\int \frac{2}{1 + e ^{2 x}} d x

(cos^{2} (x) - 2 sin (x))^{^{'}}

\int \frac{sec ^{2} ( x )}{1 + 2 tan ( x )} d x

What is the integral of (cot^2(x))/(cos^2(x)) ?
The integral of (cot^2(x))/(cos^2(x)) is -cot(x)+C