What is the limit as n approaches infinity of 1/(log_{2)(n)} ?

The limit as n approaches infinity of 1/(log_{2)(n)} is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as n approaches infinity of 1/(log_{2)(n)}

n \to \infty lim (\frac{1}{lo g _{2} ( n )})

0

Solution steps

n \to \infty lim (\frac{1}{lo g _{2} ( n )})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{lim _{n \to \infty} ( 1 )}{lim _{n \to \infty} ( lo g _{2} ( n ) )}

n \to \infty lim (1) = 1

n \to \infty lim (lo g_{2} (n)) = \infty

= \frac{1}{\infty}

Apply Infinity Property:

\frac{c}{\infty} = 0

= 0

\frac{d}{d x} (x^{k})

x \to \infty lim (- \frac{1}{3})

\int \frac{x + arcsin ( x )}{1 - x ^{2}} d x

\frac{d}{d x} (\frac{( x ^{2} )}{2 + x})

\frac{1}{x - 4}

What is the limit as n approaches infinity of 1/(log_{2)(n)} ?
The limit as n approaches infinity of 1/(log_{2)(n)} is 0