What is the derivative of x^2+4/(x^2) ?

The derivative of x^2+4/(x^2) is 2x-8/(x^3)

What is the first derivative of x^2+4/(x^2) ?

The first derivative of x^2+4/(x^2) is 2x-8/(x^3)

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\frac{d}{d x} (x^{2} + \frac{4}{x ^{2}})

2 x - \frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} (x^{2} + \frac{4}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{4}{x ^{2}})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{4}{x ^{2}}) = - \frac{8}{x ^{3}}

= 2 x - \frac{8}{x ^{3}}

x \to 6 lim (- 5 x^{2} + 6 x + 8)

\int 5000 (1 - \frac{100}{( x + 10 ) ^{2}}) d x

\frac{\partial}{\partial y} (\frac{9 x ^{2}}{y ^{\frac{1}{3}}})

\frac{d}{d x} (x^{4} - 2 x^{2} + 2)

f (x) = \frac{x ^{2}}{1 + 8 x}

What is the derivative of x^2+4/(x^2) ?
The derivative of x^2+4/(x^2) is 2x-8/(x^3)
What is the first derivative of x^2+4/(x^2) ?
The first derivative of x^2+4/(x^2) is 2x-8/(x^3)