What is the solution for (dx)/(dt)=(2t^2+x^2)/(tx) ?

The solution for (dx)/(dt)=(2t^2+x^2)/(tx) is x=tsqrt(4ln(t)+c_{1)},x=-tsqrt(4ln(t)+c_{1)}

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(dx)/(dt)=(2t^2+x^2)/(tx)

\frac{d x}{d t} = \frac{2 t ^{2} + x ^{2}}{t x}

x = t 4 ln (t) + c_{1}, x = - t 4 ln (t) + c_{1}

Solution steps

\frac{d x}{d t} = \frac{2 t ^{2} + x ^{2}}{t x}

Solve Bernoulli ODE:

x = t 4 ln (t) + c_{1}, x = - t 4 ln (t) + c_{1}

x = t 4 ln (t) + c_{1}, x = - t 4 ln (t) + c_{1}

\frac{d ^{2}}{d x ^{2}} (x^{\frac{1}{2}})

\frac{\partial}{\partial s} (arctan (rs))

f (x) = \frac{6}{x}, at x = - 7

(x^{3} + 4 x + 7) 5 + \frac{1}{x ^{2}}

x \to 7 + lim (\frac{x + 6}{x - 7})

What is the solution for (dx)/(dt)=(2t^2+x^2)/(tx) ?
The solution for (dx)/(dt)=(2t^2+x^2)/(tx) is x=tsqrt(4ln(t)+c_{1)},x=-tsqrt(4ln(t)+c_{1)}