What is the integral of (5x^2)/((3+x^3)^2) ?

The integral of (5x^2)/((3+x^3)^2) is -5/(3(3+x^3))+C

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integral of (5x^2)/((3+x^3)^2)

\int \frac{5 x ^{2}}{( 3 + x ^{3} ) ^{2}} d x

- \frac{5}{3 ( 3 + x ^{3} )} + C

Solution steps

\int \frac{5 x ^{2}}{( 3 + x ^{3} ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{x ^{2}}{( 3 + x ^{3} ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{3 u ^{2}} d u

= 5 \cdot \int \frac{1}{3 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \frac{1}{3} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= 5 \cdot \frac{1}{3} (- \frac{1}{u})

Substitute back

u = 3 + x^{3}

= 5 \cdot \frac{1}{3} (- \frac{1}{3 + x ^{3}})

Simplify

5 \cdot \frac{1}{3} (- \frac{1}{3 + x ^{3}}) : - \frac{5}{3 ( 3 + x ^{3} )}

= - \frac{5}{3 ( 3 + x ^{3} )}

Add a constant to the solution

= - \frac{5}{3 ( 3 + x ^{3} )} + C

\int (x^{3} + \frac{1}{x}) d x

\frac{\partial}{\partial y} (\frac{( x - y )}{( x + y )})

\int 4 x ln (5 x) d x

y^{^{'}} = 4 y^{2} + x y^{2}, y (0) = 1

\frac{d}{d x} (\frac{sin ( 3 x )}{7 x})

What is the integral of (5x^2)/((3+x^3)^2) ?
The integral of (5x^2)/((3+x^3)^2) is -5/(3(3+x^3))+C