What is the solution for y^'=(x^{10})/y ?

The solution for y^'=(x^{10})/y is y=sqrt((2x^{11))/(11)+c_{1}},y=-sqrt((2x^{11))/(11)+c_{1}}

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y^'=(x^{10})/y

y^{^{'}} = \frac{x ^{10}}{y}

y = \frac{2 x ^{11}}{11} + c_{1}, y = - \frac{2 x ^{11}}{11} + c_{1}

Solution steps

y^{'} (x) = \frac{x ^{10}}{y}

Solve separable ODE:

y = \frac{2 x ^{11}}{11} + c_{1}, y = - \frac{2 x ^{11}}{11} + c_{1}

y = \frac{2 x ^{11}}{11} + c_{1}, y = - \frac{2 x ^{11}}{11} + c_{1}

\frac{\partial}{\partial x} (3 x + y)

\int (- 2 x^{- 1}) d x

cos (2 \cdot t)

\frac{d y}{d x} = (x - 3) e^{- 2 y}, y (3) = ln (3)

y = lo g_{2} (lo g_{2} (x))

What is the solution for y^'=(x^{10})/y ?
The solution for y^'=(x^{10})/y is y=sqrt((2x^{11))/(11)+c_{1}},y=-sqrt((2x^{11))/(11)+c_{1}}