What is the solution for (1-xy)dx+(xy-x^2)dy=0 ?

The solution for (1-xy)dx+(xy-x^2)dy=0 is y=x+sqrt(x^2-2(ln(x)-c_{1))},y=x-sqrt(x^2-2(ln(x)-c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1-xy)dx+(xy-x^2)dy=0

(1 - x y) d x + (x y - x^{2}) d y = 0

y = x + x^{2} - 2 (ln (x) - c_{1}), y = x - x^{2} - 2 (ln (x) - c_{1})

Solution steps

(1 - x y) d x + (x y - x^{2}) d y = 0

Solve exact ODE:

y = x + x^{2} - 2 (ln (x) - c_{1}), y = x - x^{2} - 2 (ln (x) - c_{1})

y = x + x^{2} - 2 (ln (x) - c_{1}), y = x - x^{2} - 2 (ln (x) - c_{1})

\int tan^{2} (x) x d x

5 tan^{2} (9 x)

\frac{\partial}{\partial x} (- y^{2} sin (z))

\int_{3}^{11} x d x

n = 1 \sum \infty (\frac{4}{7})^{n}

What is the solution for (1-xy)dx+(xy-x^2)dy=0 ?
The solution for (1-xy)dx+(xy-x^2)dy=0 is y=x+sqrt(x^2-2(ln(x)-c_{1))},y=x-sqrt(x^2-2(ln(x)-c_{1))}