What is the integral of sin(θ)cos(θ) ?

The integral of sin(θ)cos(θ) is (sin^2(θ))/2+C

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integral of sin(θ)cos(θ)

\int sin (θ) cos (θ) d θ

\frac{sin ^{2} ( θ )}{2} + C

Solution steps

\int sin (θ) cos (θ) d θ

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (θ)

= \frac{sin ^{2} ( θ )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( θ )}{2} + C

\int_{- 2}^{3} \frac{1}{x ^{4}} d x

f (x) = (4 x + 4)^{\frac{1}{2}}

2 y^{^{''}} + 5 y^{^{'}} + 3 y = 0

\int \frac{1}{2 x + 1} d x

\int \frac{3}{16} x^{2} d x

What is the integral of sin(θ)cos(θ) ?
The integral of sin(θ)cos(θ) is (sin^2(θ))/2+C