What is the integral from 0 to 4 of pi(y-(y^2)/4) ?

The integral from 0 to 4 of pi(y-(y^2)/4) is pi 8/3

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integral from 0 to 4 of pi(y-(y^2)/4)

\int_{0}^{4} π (y - \frac{y ^{2}}{4}) d y

π \frac{8}{3}

Decimal Notation

8.37758 \dots

Solution steps

\int_{0}^{4} π (y - \frac{y ^{2}}{4}) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{4} y - \frac{y ^{2}}{4} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{4} y d y - \int_{0}^{4} \frac{y ^{2}}{4} d y)

\int_{0}^{4} y d y = 8

\int_{0}^{4} \frac{y ^{2}}{4} d y = \frac{16}{3}

= π (8 - \frac{16}{3})

Join

8 - \frac{16}{3} : \frac{8}{3}

= π \frac{8}{3}

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\frac{d}{d x} ((4 x - 21) ln ((2 x - 11) (x - 5)))

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What is the integral from 0 to 4 of pi(y-(y^2)/4) ?
The integral from 0 to 4 of pi(y-(y^2)/4) is pi 8/3