What is area y=|x|+|x-1|,x=-1,x=2 ?

The answer to area y=|x|+|x-1|,x=-1,x=2 is 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=|x|+|x-1|,x=-1,x=2

area

y = ∣ x ∣ + ∣ x - 1 ∣, x = - 1, x = 2

5

Solution steps

Apply the area formula:

\int_{- 1}^{2} ∣ ∣ x ∣ + ∣ x - 1 ∣ ∣ d x

Solve

\int_{- 1}^{2} ∣ ∣ x ∣ + ∣ x - 1 ∣ ∣ d x : 5

The area is:

= 5

\frac{d}{d x} (\frac{( x ^{3} + i x ^{2} + x + 1 )}{x ^{2} + i})

\int (1 - y) d y

\frac{d y}{d t} + 0.3 t y = 5 t, y (0) = 6

x \to 3 + lim (\frac{8}{x - 3})

\frac{d}{d x} (2 sin (x) - cos (x))

What is area y=|x|+|x-1|,x=-1,x=2 ?
The answer to area y=|x|+|x-1|,x=-1,x=2 is 5