What is (\partial)/(\partial x)(yze^{xz}-2) ?

The answer to (\partial)/(\partial x)(yze^{xz}-2) is e^{zx}yz^2

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(\partial)/(\partial x)(yze^{xz}-2)

\frac{\partial}{\partial x} (yz e^{x z} - 2)

e^{z x} y z^{2}

Solution steps

\frac{\partial}{\partial x} (yz e^{x z} - 2)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (yz e^{x z}) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (yz e^{x z}) = y z^{2} e^{z x}

\frac{\partial}{\partial x} (2) = 0

= y z^{2} e^{z x} - 0

Simplify

= e^{z x} y z^{2}

\int_{0}^{\infty} x e^{- \frac{x}{y}} d x

y^{^{''}} - 6 y^{^{'}} + 7 y = 0

\frac{\partial}{\partial x} (arctan (x) y)

(x - 1)^{3}, x - 1

\frac{d}{d x} (x^{2} - 2)

What is (\partial)/(\partial x)(yze^{xz}-2) ?
The answer to (\partial)/(\partial x)(yze^{xz}-2) is e^{zx}yz^2