What is the first d/(dt)(9sin(t)) ?

The first d/(dt)(9sin(t)) is 9cos(t)

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d/(dt)(9sin(t))

\frac{d}{d t} (9 sin (t))

9 cos (t)

Solution steps

\frac{d}{d t} (9 sin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d t} (sin (t))

Apply the common derivative:

\frac{d}{d t} (sin (t)) = cos (t)

= 9 cos (t)

\frac{d}{d t} (t e^{t} cot (t))

\frac{5}{s ^{4}}

y^{^{'}} = - x

\frac{d}{d x} (200 x - 0.2 x^{\frac{5}{2}})

n = 1 \sum \infty n^{5} (1 + n^{6})^{3}