What is the derivative of te^{2x} ?

The derivative of te^{2x} is te^{2x}*2

What is the first derivative of te^{2x} ?

The first derivative of te^{2x} is te^{2x}*2

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\frac{d}{d x} (t e^{2 x})

t e^{2 x} \cdot 2

Solution steps

\frac{d}{d x} (t e^{2 x})

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= t \frac{d}{d x} (e^{2 x})

Apply the chain rule:

e^{2 x} \frac{d}{d x} (2 x)

= e^{2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= t e^{2 x} \cdot 2

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x})

y = x, 0, 1

\int \frac{8 x ^{7}}{x ^{8} - 1} d x

f (t) = e^{7 t \cdot s i n (2 t)}

\frac{d}{d x} ((1 - 2 x)^{3})

What is the derivative of te^{2x} ?
The derivative of te^{2x} is te^{2x}*2
What is the first derivative of te^{2x} ?
The first derivative of te^{2x} is te^{2x}*2