What is the derivative of (sin(θ))/3+c/θ ?

The derivative of (sin(θ))/3+c/θ is 1/3 cos(θ)-c/(θ^2)

What is the first derivative of (sin(θ))/3+c/θ ?

The first derivative of (sin(θ))/3+c/θ is 1/3 cos(θ)-c/(θ^2)

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derivative of

\frac{sin ( θ )}{3} + \frac{c}{θ}

\frac{1}{3} cos (θ) - \frac{c}{θ ^{2}}

Solution steps

\frac{d}{d θ} (\frac{sin ( θ )}{3} + \frac{c}{θ})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (\frac{sin ( θ )}{3}) + \frac{d}{d θ} (\frac{c}{θ})

\frac{d}{d θ} (\frac{sin ( θ )}{3}) = \frac{1}{3} cos (θ)

\frac{d}{d θ} (\frac{c}{θ}) = - \frac{c}{θ ^{2}}

= \frac{1}{3} cos (θ) - \frac{c}{θ ^{2}}

3 z

\frac{d}{d x} (\frac{1}{4} x^{4})

\int 3 x cos (4 x) d x

\int \frac{3 x ^{2} - 1}{( x - 1 ) x ^{2}} d x

\frac{d}{d x} (e^{c o s (x)})

What is the derivative of (sin(θ))/3+c/θ ?
The derivative of (sin(θ))/3+c/θ is 1/3 cos(θ)-c/(θ^2)
What is the first derivative of (sin(θ))/3+c/θ ?
The first derivative of (sin(θ))/3+c/θ is 1/3 cos(θ)-c/(θ^2)