What is area f(x)=cos(x),g(x)=-cos(x)+2 ?

The answer to area f(x)=cos(x),g(x)=-cos(x)+2 is 4pi

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area f(x)=cos(x),g(x)=-cos(x)+2

area

f (x) = cos (x), g (x) = - cos (x) + 2

4 π

Decimal Notation

12.56637 \dots

Solution steps

Apply the area formula:

\int_{0}^{2 π} ∣ cos (x) - (- cos (x) + 2) ∣ d x

Solve

\int_{0}^{2 π} ∣ cos (x) - (- cos (x) + 2) ∣ d x : 4 π

The area is:

= 4 π

(- 1.4) (3.12)

y = (- x^{2} + 10 x - 21)^{3}

\frac{d}{d x} (\frac{3 x + 2}{cos ( x )})

\frac{d}{d x} (e^{x} - e^{x c o s (x)})

\int_{0}^{3} \frac{4}{5 x ^{2} + 6 x + 1} d x

What is area f(x)=cos(x),g(x)=-cos(x)+2 ?
The answer to area f(x)=cos(x),g(x)=-cos(x)+2 is 4pi