What is (\partial)/(\partial y)(sin(2y)) ?

The answer to (\partial)/(\partial y)(sin(2y)) is cos(2y)*2

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(\partial)/(\partial y)(sin(2y))

\frac{\partial}{\partial y} (sin (2 y))

cos (2 y) \cdot 2

Solution steps

\frac{\partial}{\partial y} (sin (2 y))

Apply the chain rule:

cos (2 y) \frac{\partial}{\partial y} (2 y)

= cos (2 y) \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 y) = 2

= cos (2 y) \cdot 2

\int_{0}^{3} \frac{2 t}{( t - 4 ) ^{2}} d t

\frac{x ^{2} - 3 x + 2}{- x ^{2} - 4 x + 4}

\frac{\partial}{\partial x} (y^{4} sin (5 x))

\frac{1}{s ^{2} + 9}

What is (\partial)/(\partial y)(sin(2y)) ?
The answer to (\partial)/(\partial y)(sin(2y)) is cos(2y)*2