What is the integral of cos^2(x)sec^2(x) ?

The integral of cos^2(x)sec^2(x) is x+C

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integral of cos^2(x)sec^2(x)

\int cos^{2} (x) sec^{2} (x) d x

x + C

Solution steps

\int cos^{2} (x) sec^{2} (x) d x

Express with sin, cos

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

n = 0 \sum \infty \frac{1}{5 n}

\int \frac{1 - x}{1 + x} \cdot \frac{1}{x ^{2}} d x

\int_{t}^{0} \frac{1}{1 + x ^{2}} d x

f (x) = \frac{40}{0.01 x ^{2} + 1}

\frac{d}{d x} (3 x + 3)

What is the integral of cos^2(x)sec^2(x) ?
The integral of cos^2(x)sec^2(x) is x+C