What is the integral of e^{-st}sin(t) ?

The integral of e^{-st}sin(t) is -(e^{-st}cos(t))/(1+s^2)-(se^{-st}sin(t))/(1+s^2)+C

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integral of e^{-st}sin(t)

\int e^{- s t} sin (t) d t

- \frac{e ^{- s t} cos ( t )}{1 + s ^{2}} - \frac{s e ^{- s t} sin ( t )}{1 + s ^{2}} + C

Solution steps

\int e^{- s t} sin (t) d t

Apply Integration By Parts

: - e^{- s t} cos (t) - \int s e^{- s t} cos (t) d t

= - e^{- s t} cos (t) - \int s e^{- s t} cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{- s t} cos (t) - s \cdot \int e^{- s t} cos (t) d t

Apply Integration By Parts

: e^{- s t} sin (t) - \int - s e^{- s t} sin (t) d t

= - e^{- s t} cos (t) - s (e^{- s t} sin (t) - \int - s e^{- s t} sin (t) d t)

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{- s t} cos (t) - s (e^{- s t} sin (t) - (- s \cdot \int e^{- s t} sin (t) d t))

Therefore

\int e^{- s t} sin (t) d t = - e^{- s t} cos (t) - s (e^{- s t} sin (t) - (- s \cdot \int e^{- s t} sin (t) d t))

Isolate

\int e^{- s t} sin (t) d t

= - \frac{e ^{- s t} cos ( t )}{1 + s ^{2}} - \frac{s e ^{- s t} sin ( t )}{1 + s ^{2}}

Add a constant to the solution

= - \frac{e ^{- s t} cos ( t )}{1 + s ^{2}} - \frac{s e ^{- s t} sin ( t )}{1 + s ^{2}} + C

f (x) = 16 - x^{2}

\int_{1}^{\infty} \frac{1}{9 x + 2} d x

(x - 3) e^{x}

\int tan (x) + 2 cot (x) d x

What is the integral of e^{-st}sin(t) ?
The integral of e^{-st}sin(t) is -(e^{-st}cos(t))/(1+s^2)-(se^{-st}sin(t))/(1+s^2)+C