What is area x=-2,x=3,y=2x^2+10,y=0 ?

The answer to area x=-2,x=3,y=2x^2+10,y=0 is 220/3

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area x=-2,x=3,y=2x^2+10,y=0

area

x = - 2, x = 3, y = 2 x^{2} + 10, y = 0

\frac{220}{3}

Decimal Notation

73.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} 2 x^{2} + 10 d x

Solve

\int_{- 2}^{3} 2 x^{2} + 10 d x : \frac{220}{3}

The area is:

= \frac{220}{3}

f (x) = 9 e^{x} cos (x), at x = 0

\frac{\partial}{\partial v} (4 u cos (v))

\frac{\partial}{\partial x} (\frac{1}{1 + e ^{- x}})

\int \frac{sin ( 3 x )}{3} d x

\int \frac{- x}{1 + x} d x

What is area x=-2,x=3,y=2x^2+10,y=0 ?
The answer to area x=-2,x=3,y=2x^2+10,y=0 is 220/3