What is laplacetransform 3e^{(-2t)} ?

The answer to laplacetransform 3e^{(-2t)} is 3/(s+2)

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laplacetransform 3e^{(-2t)}

laplace transform

3 e^{(- 2 t)}

\frac{3}{s + 2}

Solution steps

L {3 e^{(- 2 t)}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= 3 \cdot \frac{1}{s + 2}

Refine

3 \frac{1}{s + 2} : \frac{3}{s + 2}

= \frac{3}{s + 2}

y = \frac{4}{x}, y = 8 x, y = \frac{1}{8} x

\frac{π}{9} cos (θ)

\int_{0}^{1} x^{2} 1 - x^{2} d x

f (x) = x sin (2 x)

y^{^{'}} = \frac{4 y}{x}

What is laplacetransform 3e^{(-2t)} ?
The answer to laplacetransform 3e^{(-2t)} is 3/(s+2)