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Popular >

y^'=(2t+1)e^y

Solution

y^{^{'}} = (2 t + 1) e^{y}

Solution

y = - ln (- t^{2} - t - c_{1})

Solution steps

y^{'} (t) = (2 t + 1) e^{y}

Solve separable ODE:

y = - ln (- t^{2} - t - c_{1})

y = - ln (- t^{2} - t - c_{1})

Popular Examples

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\frac{d}{d z} (z + 1 - 1)

slope of x^2+8x+2 slope

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(2t+1)e^y ?
The solution for y^'=(2t+1)e^y is y=-ln(-t^2-t-c_{1})