What is the integral of 10xsec(x)tan(x) ?

The integral of 10xsec(x)tan(x) is 10(xsec(x)-ln|tan(x)+sec(x)|)+C

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integral of 10xsec(x)tan(x)

\int 10 x sec (x) tan (x) d x

10 (x sec (x) - ln ∣ tan (x) + sec (x) ∣) + C

Solution steps

\int 10 x sec (x) tan (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int x sec (x) tan (x) d x

Apply Integration By Parts

: x sec (x) - \int sec (x) d x

= 10 (x sec (x) - \int sec (x) d x)

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= 10 (x sec (x) - ln ∣ tan (x) + sec (x) ∣)

Add a constant to the solution

= 10 (x sec (x) - ln ∣ tan (x) + sec (x) ∣) + C

\frac{\partial}{\partial x} (ln (2 x + 3 y + 6 z))

\int x^{- 0.1} d x

\frac{d}{d x} (\frac{ln ( x )}{x ^{6}})

\frac{d}{d x} (2 x - 2)

\int \frac{x ^{2} - 484}{x} d x

What is the integral of 10xsec(x)tan(x) ?
The integral of 10xsec(x)tan(x) is 10(xsec(x)-ln|tan(x)+sec(x)|)+C